If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-2x^2+28x-96=0
a = -2; b = 28; c = -96;
Δ = b2-4ac
Δ = 282-4·(-2)·(-96)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4}{2*-2}=\frac{-32}{-4} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4}{2*-2}=\frac{-24}{-4} =+6 $
| 4f-3f=16 | | 5-2x-10=10 | | 8x+-2=12+7x | | 7t-4=10+4 | | -4x+3(6x-26)=-148 | | x^-6x+12=0 | | 4^x-3=128 | | 2-(3-2(x+1)=3x+2(3x+2(x-(3+2x) | | 30-4x+10=60 | | 6p=3p-18 | | 3x(4x-15)=180 | | 12+0.5x=18+2.0x | | 5x-7(5x-25)=5 | | 30-4x+10=-60 | | 5(3x+4)-2x=7x-3(-2x+11 | | a-6=36 | | 9x-4=2x/3 | | -6.8(x-3.75)=20.4 | | x-5-(2-x)=13 | | x2/3=36 | | 5(x-4)+2=18 | | 96=-2x-4(-6x+31) | | 4/9+(x-1)=28/9-(x-7)+1 | | -8n+n=-8n-8n | | 12p-16=-7 | | 15r+12=-8 | | 7g+9=5g+10 | | 20-5x-2=-12 | | 17x-13=-3x+5(6-4×) | | -393=-5x+7(-7x+21) | | 4/(x+12)-3/(x-12)=5x/x^2-144 | | 10+30r=-86 |